Exactly.

We'll repeat that from the last time.

I promised you I would draw it again.

It's nice that this happens.

Unfortunately, I have to say that if you look at the recording of the exercise, we had

enough technical problems, but there was more to it.

Unfortunately, the sound is now always gone when the scene change came to the pre-reading

the video.

I didn't cut the sound in the video because there were ten parts.

You can do that later.

I'll leave it to you.

Do it quietly.

Exactly.

We were at the last time.

We looked at the crystal levels.

We looked at Miller indices and did different things.

We first did a little bit of the

We first drew Miller indices

determined by given levels

parallel to the levels from

which we determined the Miller indices, that is, what we always do.

We determine the interfaces with the axes, we build the reverse value, multiply with the

smallest common multiple and always determine the Miller indices.

For example, 111.

All these three levels have the Miller indices 111.

That's the beauty of the Miller indices.

You know how to determine them.

You know why we determine them and how we draw parallel

equivalent grid levels in

a crystal and then also determine them.

What we did next was that we actually specified a certain level

or rather

we

had specified the interfaces with the coordinate axes.

222 had already determined in 2B that the Miller indices are 111.

Then we should consider how we can ensure that a vector hkl on a level hkl

in this

case this level, is vertical.

We did the whole thing.

We set the level equations

determined the normal vector and also set the level equations

in normal form and then looked at the conditions for which the level or the form is given

or for which conditions the vector is normally on the level.

And that's why I've just drawn you again in peace with a linear

how the whole thing

looks or what support and tension vectors are and how to determine a level equation or

how to determine these vectors.

And we had said last time

level equation was this one.

We have the support vector plus lambda times one tension vector plus mu times the second